57=4x^2/(0.2-x)(0.1-x)

Solution for 57=4x^2/(0.2-x)(0.1-x) equation:

57=4x^2/(0.2-x)(0.1-x)

We move all terms to the left:

57-(4x^2/(0.2-x)(0.1-x))=0


Domain of the equation: (0.2-x)(0.1-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)(0.1-x)!=-0.2

x∈R


We add all the numbers together, and all the variables

-(4x^2/(-1x+0.2)(-1x+0.1))+57=0

We multiply parentheses ..

-(4x^2/(+x^2-0.1x-0.2x+0.02))+57=0

We multiply all the terms by the denominator


-(4x^2+57*(+x^2-0.1x-0.2x+0.02))=0


We calculate terms in parentheses: -(4x^2+57*(+x^2-0.1x-0.2x+0.02)), so:

4x^2+57*(+x^2-0.1x-0.2x+0.02)

We multiply parentheses

4x^2+57x^2+0x+0x+1.14

We add all the numbers together, and all the variables

61x^2+2x+1.14

Back to the equation:

-(61x^2+2x+1.14)


We get rid of parentheses

-61x^2-2x-1.14=0

a = -61; b = -2; c = -1.14;
Δ = b2-4ac
Δ = -22-4·(-61)·(-1.14)
Δ = -274.16
Delta is less than zero, so there is no solution for the equation